[tex]0 \leq \displaystyle \lim_{n \to \infty} \frac{n!}{(2n)!} \leq \displaystyle \lim_{n \to \infty} \frac{n!}{(n!)^{2}} =[/tex]
[tex]0 \leq \displaystyle \lim_{n \to \infty} \frac{n!}{(2n)!} \leq \displaystyle \lim_{n \to \infty} \frac{n!}{(n!)^{2}} =[/tex]
[tex] \displaystyle \lim_{k \to \infty ,k = n!} \frac{k}{ {k}^{2} } = [/tex]
[tex] \displaystyle \lim_{k \to \infty } \frac{1}{k} = [/tex]
[tex] \frac{1}{ \infty } = [/tex]
[tex]0[/tex]
[answer.2.content]
